Basic Math Examples



\begin{array}{r} b = & 3 \\ h = & 4 \end{array}

$\begin{array}{r} b = & 3 \\ h = & 4 \end{array}$

Step 1

The area of a triangle is equal to

\frac{1}{2}

$\frac{1}{2}$ the base times the height.

\frac{1}{2} \cdot (b a s e) \cdot (h e i g h t)

$\frac{1}{2} \cdot (b a s e) \cdot (h e i g h t)$

Step 2

Substitute the values of the base

b = 3

$b = 3$ and height

h = 4

$h = 4$ into the formula for the area of a triangle.

\frac{1}{2} \cdot 3 \cdot 4

$\frac{1}{2} \cdot 3 \cdot 4$

Step 3

Combine

\frac{1}{2}

$\frac{1}{2}$ and

3

$3$ .

\frac{3}{2} \cdot 4

$\frac{3}{2} \cdot 4$

Step 4

Cancel the common factor of

2

$2$ .

Tap for more steps...

Step 4.1

Factor

2

$2$ out of

4

$4$ .

\frac{3}{2} \cdot (2 (2))

$\frac{3}{2} \cdot (2 (2))$

Step 4.2

Cancel the common factor.

\frac{3}{2} \cdot (2 \cdot 2)

$\frac{3}{2} \cdot (2 \cdot 2)$

Step 4.3

Rewrite the expression.

3 \cdot 2

$3 \cdot 2$

3 \cdot 2

$3 \cdot 2$

Step 5

Multiply

3

$3$ by

2

$2$ .

6

$6$



\begin{array}{r} h = & 4 \\ b = & 3 \end{array}

$\begin{array}{r} h = & 4 \\ b = & 3 \end{array}$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$